12s^2-25s+2=0

Solution for 12s^2-25s+2=0 equation:

12s^2-25s+2=0

a = 12; b = -25; c = +2;
Δ = b2-4ac
Δ = -252-4·12·2
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-23}{2*12}=\frac{2}{24}
=1/12
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+23}{2*12}=\frac{48}{24}
=2
$